Delliriumzz Delliriumzz
  • 09-12-2020
  • Mathematics
contestada

Which equation has the solutions x=1+/- 5?
Ox^2+2x + 4 =0
Ox^2-2x + 4 =0
Ox^2+ 2x-4 = 0
Ox^2-2x – 4 =0

Respuesta :

yailet7
yailet7 yailet7
  • 09-12-2020

Answer:

[tex]x^{2} -2x-4=0[/tex]

Solving Steps

Use the quadratic formula

[tex]x=\frac{-(-2)(+/-)\sqrt{(-2)^2-4*1*(-4)} }{2*1}[/tex]

Multiply / Remove the parentheses / Evaluate

[tex]x=\frac{2(+/-)\sqrt{4+16} }{2}[/tex]

Calculate

[tex]x=\frac{2(+/-)\sqrt{20} }{2}[/tex]

Separate the solutions

[tex]x=\frac{2(+/-)2\sqrt{5} }{2} \\x=\frac{2-2\sqrt{5} }2}[/tex]

Simplify

[tex]x=1+\sqrt{5} \\x=1-\sqrt{5}[/tex]

Answer Link

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