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Answer:

0.6 moles NH₃

Explanation:

The reaction that takes place is:

  • N₂ + 3H₂ → 2NH₃

First we determine the limiting reactant:

  • 0.35 mol N₂ would react completely with (3*0.35) 1.05 moles of H₂. There are not as many H₂ moles, so H₂ is the limiting reactant.

Then we convert H₂ moles (the limiting reactant) to NH₃ moles, keeping in mind the stoichiometry of the reaction:

  • 0.90 mol H₂ * [tex]\frac{2molNH_3}{3molH_2}[/tex]= 0.6 moles NH₃

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