Answer:
1. In a group of cows and chickens, the number of legs was 14 more than twice the number ... m = 4500/15 000 m = 3/10 m = 0.3. Now, put the value of m = 0.3 in equation (i) we get; ... (4x3 + 7x2 – 13x – 3) ÷ (x + 3) by using synthetic division.
