Answer:
The value of H(F(-2)) is 379
Step-by-step explanation:
Soln,
Given,
F(x)= 2x^2+4x+10
G(x)= 3x-11
H(x)= 3x^2+x^2-21
Now,
F(-2) = 2(-2)^2 + 4×(-2) + 10
= 2×4 + (-8) + 10
= 8-8+10
= 18 - 8
= 10
Again,
H(F(-2)) = 3x^2 + x^2 - 21
Putting the value of F(-2) , we get
H(10) = 3×10^2 + 10^2 - 21
= 3×100 + 100 - 21
= 300 + 100 - 21
= 400 - 21
= 379
Therefore, H(F(-2)) = 379.
