casonnicole21
casonnicole21 casonnicole21
  • 06-10-2016
  • Mathematics
contestada

Answer is due in 1 hour!

Find an equation of the tangent line to the curve
y = 10x sin x
at the point (π/2, 5π).

Respuesta :

chanit
chanit chanit
  • 06-10-2016
 y = 10x * sin(x) 
y' = 10 * (x * cos(x) + sin(x)) 
x = pi/2 
y' = 10 * ((pi/2) * cos(pi/2) + sin(pi/2)) = 10 * ((pi/2) * 0 + 1) = 10 * 1 = 10 
y - 5pi = 10 * (x - (pi/2)) 
y - 5pi = 10x - 5pi 
y = 10x
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