Respuesta :

HermanSlader

Answer:

$\sqrt[3]{27x^6y^4}=3 x^2\sqrt[3]{y^4}$

Step-by-step explanation:

[tex]\sqrt[3]{27x^6y^4}= \sqrt[3]{3^3x^6y^4}\\\sqrt[3]{27x^6y^4}=\sqrt[3]{3^3} \sqrt[3]{x^6} \sqrt[3]{y^4}[/tex]

therefore,

[tex]\sqrt[3]{27x^6y^4}=3 x^2\sqrt[3]{y^4}[/tex]