Answer:
[tex]\frac{2\sqrt{3} + 32}{2} \\[/tex]
Step-by-step explanation:
[tex]\frac{\sqrt{12} }{2} + 16[/tex]
= [tex]\frac{\sqrt{12} }{2} + \frac{32}{2}[/tex]
= [tex]\frac{\sqrt{12} + 32}{2}[/tex]
= [tex]\frac{2\sqrt{3} + 32}{2} \\[/tex]
* i'm not sure if it can be further broken down *
