Answer:
#Horizontal component of 100m/s=100 sin60=50×(root 3)=50×1.732=86.6m/s
#Vertical component of 100m/s=100 cos 60°=100/2=50m/s
(¡) Maximum height it can reach=(v^2+u^2) /2a=0+(50^2) / 2×(-10)=125m
(¡¡) The time takes to reach the maximum height =2S/(u-v)=125×2/(50-0)=5s
(¡¡¡) Horizontal range=ut=86.6×5=433m
Explanation:
# At the highest point (vertical) velocity is zero
#Velocity (horizontal) remains constant
(¡)By v^2=u^2+2as equation
(¡¡)By S=1/2(u+v)t equation
(¡¡¡) S=ut therefore horizontal range=ut
