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Calculate the standard potential for a cell that employs the over-all cell reaction: 2Al(s) + 3 I2(s)ā†’2 Al+3 + 6 I- From reduction potential table: Al+3 (aq) + 3e- ā†’ Al(s) -1.66 V I2(s) + 2e- ā†’ 2I- -0.54 V

Respuesta :

Answer:

Explanation:

2Al(s) + 3 Iā‚‚(s) Ā  ā†’ Ā  Ā 2 AlāŗĀ³ Ā  Ā + Ā  Ā  6 Iā»

Aluminium is oxidised and iodine is reduced .

so cell potential = Ereduction - Eoxidation

AlāŗĀ³ + 3e = Al Ā  Ā  Ā  Ā  Ā - Ā 1.66 V

Iā‚‚ + 2 e = 2 Iā» Ā  Ā  Ā  Ā  Ā  Ā  0.54 V

= Ā .54 - ( - 1.66 )

= 1.66 + .54

= 2.2 Ā V

The overall standard cell potential for the given cell that employs the overall cell reaction is; EĀ°_cell = 2.20 V

We are given the cell reaction;

2Al (s) + 3Iā‚‚ (s) ā†’ 2AlāŗĀ³ + 6Iā»

We are given reduction potential as;

AlāŗĀ³(aq) + 3eā» ā†’ Al(s) ;EĀ°_red = -1.66 V

However, the standard reduction potential for the reverse of the oxidation reaction is;

Al ā†’ AlāŗĀ³(aq) + 3eā» ;EĀ°_ox = 1.66 V

We are also given;

Iā‚‚ + 2eā» = 2Iā» ;EĀ°_red = 0.54 V

To get Ā overall standard cell potential, we will add the cell potentials to get;

EĀ°_cell = EĀ°_ox + EĀ°_red

EĀ°_cell = 1.66 + 0.54

EĀ°_cell = 2.20 V

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