Answer:
a = 11 , b = 2
Step-by-step explanation:
[tex]\frac{(4-\sqrt{5})(4+\sqrt{5}) }{2\sqrt{11}} = \frac{ \sqrt{a}}{y} \\Hence,\\\frac{4^2-(\sqrt{5})^2 }{2\sqrt{11}} = \frac{ \sqrt{a}}{y}\\\frac{16-5}{2\sqrt{11} } = \frac{ \sqrt{a}}{y}\\\frac{11}{2\sqrt{11}} = \frac{ \sqrt{a}}{y}\\\frac{\sqrt{11}*\sqrt{11} }{2\sqrt{11}} = \frac{ \sqrt{a}}{y}\\\frac{\sqrt{11} }{2} = \frac{ \sqrt{a}}{y}\\a=11,b =2[/tex]
