Answer:
f(-3) = -32 for f(x) = 3(2x - 5) + 1
f(-3) = 13 for f(x) = 3(x^2 - 5) + 1
Step-by-step explanation:
f(x) = 3 (2x - 5) + 1
f(-3) = 3 (2(-3) - 5) + 1
f(-3) = 3( -6 - 5 ) + 1
f(-3) = 3( -11 ) + 1
f(-3) = -33 + 1
f(-3) = -32
_________
f(x) = 3(x^2 - 5) + 1
f(-3) = 3((-3)^2 - 5) + 1
f(-3) = 3(9 - 5) + 1
f(-3) = 3(4) + 1
f(-3) = 12 + 1
f(-3) = 13
