melissa12bonilla
melissa12bonilla melissa12bonilla
  • 10-10-2020
  • Mathematics
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How many gallons of 25% alcohol solution and 40% alcohol solution must be mixed to get 6 gallons of 30%
alcohol solution?

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Аноним Аноним
  • 10-10-2020

Answer:

amt of 25% solution to mix=6 gal

amt of 40% solution to mix=3 gal

Step-by-step explanation:

let x=amt of 25% solution to mix

9-x=amt of 40% solution to mix

25%x+40%(9-x)=30%*9

.25x+3.6-.40x=2.7

.15x=0.90

x=6

9-x=3

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