Answer:
5.78 mol Li
Explanation:
Step 1: Define
Avagadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Step 2: Use Dimensional Analysis
[tex]3.48(10)^{24} \hspace{3} particles \hspace{3} Li(\frac{1 \hspace{3} mol \hspace{3} Li}{6.02(10)^{23} \hspace{3} particles \hspace{3} Li} )[/tex] = 5.78073 mol Li
Step 3: Simplify
We have 3 sig figs.
5.78073 mol Li ≈ 5.78 mol Li
