Respuesta :

shownubear1992

Answer:

d = 2[tex]\sqrt{3}[/tex]

Step-by-step explanation:

[tex]d= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\d= \sqrt{(3-9)^2+(6-2)^2} \\d= \sqrt{(-6)^2+(4)^2} \\d= \sqrt{(36)+(16)} \\d= \sqrt{52} \\d=2 \sqrt{13}[/tex]

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