Answer:
Step-by-step explanation:
[tex]93^\circ52'12"=93^\circ52\frac{12}{60}'=93^\circ52\frac{1}{5}'=93^\circ\frac{261}{5}'=93\frac{261}{5 \times 60}^\circ=93\frac{87}{100}^\circ=93.87^\circ[/tex]
