SubuKarki
SubuKarki SubuKarki
  • 09-09-2020
  • Mathematics
contestada

factorise 9(a+b)^2 + (a+b) -8 ​

Respuesta :

mirai123
mirai123 mirai123
  • 09-09-2020

Answer:

[tex](9a+9b-8)(a+b+1)[/tex]

Step-by-step explanation:

[tex]9(a+b)^2 + (a+b)-8[/tex]

Expand [tex](a+b)^2[/tex]

[tex]9(a^2+2ab+b^2)+a+b-8[/tex]

[tex]9a^2+18ab+9b^2+a+b-8[/tex]

Now it is time to think.

Once

[tex]9a^2=9a \cdot a[/tex]

[tex]9b^2=9b \cdot b[/tex]

[tex]18ab=9ab+9ab[/tex]

[tex]-8=-8 \cdot 1[/tex]

We can get something in the format

[tex](9a+9b-8)(\text{some expression here})[/tex]

From the conclusions above,

[tex](9a+9b-8)(a+b+1)[/tex]

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