Answer:
C) 3.37 moles
.
Explanation:
Hello,
In this case, considering that the atomic mass of aluminum is 27.0 g/mol, the moles in 90.93 g of aluminum are computed via the following dimensional analysis:
[tex]n=90.93 gAl*\frac{1molAl}{27.0gAl} \\\\n=3.37molAl[/tex]
Thus, answer is C) 3.37 moles
.
Best regards.
