KL99
KL99
10-09-2016
Mathematics
contestada
Need help solving this question B^3+1/27
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caylus
caylus
10-09-2016
Hello,
to solve we must have an equation.
If you mean factor then
[tex]b^3+ \dfrac{1}{3^3} =(b+ \dfrac{1}{3} )(b^2- \dfrac{b}{3} + \dfrac{1}{9}) [/tex]
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