ha6nnaVirgos ha6nnaVirgos

08-09-2016
Mathematics

contestada

solve y^2 4y - 32 = 0 using the zero product property.a. y=3b. y = -8, 4c. y = 8, -4d. y = -8, 6

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nobillionaireNobley nobillionaireNobley

08-09-2016

y^2 + 4y - 32 = 0
y^2 - 4y + 8y - 32 = 0
y(y - 4) + 8(y - 4) = 0
(y + 8)(y - 4) = 0
y + 8 = 0 or y - 4 = 0
y = -8 or y = 4.

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