hoanglai426 hoanglai426
  • 08-08-2020
  • Mathematics
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f(x) = x+ bx + 5 In the given function, b is a constant. If f(1) = 0, what is the value of f(3) ?

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sigup01
sigup01 sigup01
  • 08-08-2020

Answer:

f(x)= x+bx+5

f(1) = 1+ b(1) +5 =0

f(1) = 6 +b =0

6+b=0

b=-6

so we get,

f(3)= 3 -6(3)+5

f(3) = 3-18+5

f(3) = -10

hope it helps ^°^

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