cookieswirlGR
cookieswirlGR cookieswirlGR
  • 09-07-2020
  • Mathematics
contestada

I NEED HELP ASAP PLEASE! :)

I NEED HELP ASAP PLEASE class=

Respuesta :

devishri1977
devishri1977 devishri1977
  • 09-07-2020

Answer:

option 1

Step-by-step explanation:

[tex]r=\sqrt{(5\sqrt{2})^{2}+(-5\sqrt{2})^{2} } \\\\=\sqrt{25*2+25*2}\\\\ =\sqrt{50+50}\\\\=\sqrt{100}\\\\=10[/tex]

[tex]x=tan^{-1}(\frac{-5\sqrt{2}}{5\sqrt{2}})\\\\x=tan^{-1} (-1)\\x=\frac{7\pi}{4}[/tex]

[tex]re^{ix}=10e^{i\frac{7\pi}{4}}[/tex]

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