Answer: 10,370.25J
Explanation:
Given the following :
Mass of water = 550g
T1 = 20.8°C
T2 = 25.3°C
Temperature change = (T2 - T1) = (25.3 - 20.8)°C = 4.5°C
Specific heat capacity of water = 4.19Jg^-1C^-1
Recall:
Q = mc∆T
Where ∆T = temperature change, Q = quantity of heat c = specific heat capacity of water, m = mass of water in gram
Q = 550 × 4.19 × 4.5
Q = 10,370.25J
