Answer:
We can use the distributive property.
(x + 2)(y - 1)
= x(y) - x(1) + 2(y) - 2(1)
= xy - x + 2y - 2
solution,
[tex](x + 2)(y - 1) \\ = x(y - 1) + 2(y - 1) \\ = xy - x + 2y - 2[/tex]
Hope this helps...
