Answer:
6 ± i and 6 ± i
Step-by-step explanation:
Let x be the first number.
Let y be the second number.
x + y = 12
x × y = 37
Solve for x in the first equation.
x = 12 - y
Put x as 12-y in the second equation and solve for y.
(12- y)y = 37
12y - y² = 37
- y² + 12y - 37 = 0
y = 6 ± i
Put y as 6 ± i in the first equation and solve for x.
x + 6 ± i = 12
x = 12 - 6 ± i
x = 6 ± i
