Answer:
(x + 4) ^{2} + 47 = 0
Step-by-step explanation:
[tex](x ^{2} + 4 ^{2} ) - 4 ^{2} + 63 = 0 \\ (x + 4) ^{2} + 47 = 0 [/tex]
When completing squares, basing on our equation in the question:
- First square the half of 16 e.g (16÷2)^2 = 4^2
- Add the result to x^2 and subtract it with 63 e.g the second equation
