Answer:
Spring constant, k = 49 N/m
Explanation:
It is given that,
Mass that is attached to the spring is 0.5 kg
Due to this mass, the spring stretches a distance of 0.1 meter.
We need to find the spring constant of this spring. When the spring is attached to the spring, the force on spring is balanced by its weight such that,
[tex]mg=kx[/tex]
k is spring constant
[tex]k=\dfrac{mg}{x}\\\\k=\dfrac{0.5\times 9.8}{0.1}\\\\k=49\ N/m[/tex]
So, the spring constant of the spring is 49 N/m.
