A saturated solution of lead(II) nitrate was made at 50 °C using 100 g of water, and this was then allowed to cool to 30 °C. Predict what would happen as the solution cooled?

Respuesta :

A precipitate would form because, in general, solubility is less when temperature decreases.

Answer: D) The solubility would decrease and some of the lead (II) nitrate would precipitate out.