Answer:[tex]E=33.71\ J[/tex]
Explanation:
Given
No of atoms of hydrogen [tex]N=5.54\times 10^{21}[/tex]
Temperature of room [tex]T=21^{\circ}\approx 294\ K[/tex]
Thermal energy of the atoms is given by
[tex]E=\frac{3}{2}NkT[/tex]
where k=boltzmann constant
[tex]E=\frac{3}{2}\times 5.54\times 10^{21}\times 1.38\times 10^{-23}\times 294[/tex]
[tex]E=33.71\ J[/tex]
Hence the energy of the atoms is [tex]33.71\ J[/tex]
