here we are given 8x^3-27 now making both as a cube root (2x)^3-(3)^3 using formula cube root a^3-b^3=(a-b)(a^2+ab+b^2) where a=2x b=3 now putting these values 2x^3-3^3=(2x-3)(2x^2+2x*3+3^2) simplifying 2x^3-3^3=(2x-3)(4x^2+6x+9) hence the right answer is 2x^3-3^3=(2x-3)(4x^2+6x+9)
