Answer:
[tex](A)-\frac{1}{3}x[/tex]
Step-by-step explanation:
Let the term to be added = y
Therefore:
[tex]\frac{5}{6}x-4+y=\frac{1}{2}x-4 \\[/tex]
Collecting Like terms
[tex]y=\frac{1}{2}x-\frac{5}{6}x-4+4 \\=\frac{x}{2}-\frac{5x}{6}\\=\frac{3x-5x}{6}=-\frac{2x}{6}\\y=-\frac{1}{3}x[/tex]
Answer: The term that can be added is negative one-third x
[-1/3(x)]
Step-by-step explanation: Please see the attachment below
