Answer:
[tex]g=\frac{n^3+4n^2-n}{-2-n}[/tex]; [tex]n\ne \:-2[/tex]
Step-by-step explanation:
[tex]g\left(-2-n\right)=n^3+4n^2-n[/tex]
[tex]\frac{g\left(-2-n\right)}{-2-n}=\frac{n^3}{-2-n}+\frac{4n^2}{-2-n}-\frac{n}{-2-n}[/tex]; [tex]\:n\ne \:-2[/tex]
[tex]g=\frac{n^3+4n^2-n}{-2-n};\quad \:n\ne \:-2[/tex]
