alexandraangel9908 alexandraangel9908
  • 08-04-2020
  • Chemistry
contestada

Determine the Ka for CH3NH3+ at 25*C. The Kb for CH3NH2 is 4.4 x 10-4.

Respuesta :

Liuleah01 Liuleah01
  • 08-04-2020

Answer:

Ka= 2.3 x 10^-11

Explanation:

so Ka x Kb = Kw where Kw=10^-14 at 25 degrees Celsius

plugging in Kb and Kw, we have

Ka x 4.4 x 10^-4 = 10^-14

solving for Ka,

Ka= (10^-14)/(4.4 x 10^-4)

Ka= 2.3 x 10^-11

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