Answer:
Explanation:
The skateboarder moves on a circular path of radius 1.2 m with velocity 3.2 m /s so centripetal force required
= m v² / r , m is mass , v is velocity and r is radius of the circular path.
= 35 x 3.2² / 1.2
= 298.67 N
Force 45 N is provided by tree branch . The rest will be provided by frictional force
frictional force F = 298.67 - 45
= 253.67 N
weight = reaction force of ground = 35 x 9.8
= 343 N
Coefficient of friction = friction / reaction force
= 253.67 / 343
= .74 .
