Answer:
1.7 M
Explanation:
Given data:
Mass of AgNO₃ = 29.66 g
Volume of solution = 100 mL (100/1000 = 0.1 L)
Molarity of solution = ?
Solution;
Number of moles of AgNO₃:
Number of moles = mass/ molar mass
Number of moles = 29.66 g/ 169.87 g/mol
Number of moles = 0.17 mol
Molarity of solution:
Molarity = moles of solute / volume of solution in L
Molarity = 0.17 mol / 0.1 L
Molarity = 1.7 M
