alliebeech alliebeech

08-07-2016
Chemistry

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Calculate the number of kilojoules to warm 125 g of iron from 23.5°C to 78.0°C.

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olemakpadu olemakpadu

09-07-2016

m = 125 g = 125/1000 kg = 0.125 kg, θ₂ = 78.0°C, θ₁ = 23.5°C , c = 0.44kJ/kg°C,

Q = mc(θ₂ - θ₁)

Q = 0.125*0.440*(78 - 23.5)

Q = 2.9975 kJ

2.9975 kJ required to warm it.

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