nitaxoxo nitaxoxo

09-03-2020
Mathematics

contestada

x²+y²=25 xy=12 find the value of (3x+3y)²

Respuesta :

devishri1977 devishri1977

09-03-2020

Answer:

Step-by-step explanation:

(a + b)²=a²+2ab+b²

(3x+3y)²= (3x)²+2*3x*3y+(3y)²

=9x² + 18xy + 9y²

=9x² + 9y² + 18xy

= 9*(x²+y²) +18xy

=9*25 + 18*12

=225 + 216

=441

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