areynolds00airbear00
areynolds00airbear00 areynolds00airbear00
  • 06-07-2016
  • Mathematics
contestada

what is the radius of 5x^2+5y^2-20x+30y+40=0

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caylus
caylus caylus
  • 06-07-2016
Hello,
5x²+5y²-20x+30y+40=0
==>x²+y²-4x+6y+8=0 (divided by 5)
==>(x²-2*2x+4)+(y²+2*3y+9)+8-4-9=0
==>(x-2)²+(y+3)²=5

Center (2,-3)
Radius= √5≈2.2360...
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