Step-by-step explanation:
The complete question:
What is the value of y in the formula shown when x = [tex]\dfrac{4}{5}[/tex] ?
[tex]y=\dfrac{4}{x}+\sqrt{x+0.2}-5x[/tex]
We have,
[tex]\dfrac{4}{x}+\sqrt{x+0.2}-5x[/tex] ...... (1)
To find, the value of y = ?
Put x = [tex]\dfrac{4}{5}[/tex] in equation (1), we get
[tex]y=\dfrac{4}{\dfrac{4}{5}}+\sqrt{\dfrac{4}{5}+0.2}-5(\dfrac{4}{5})[/tex]
[tex]=5+\sqrt{0.8+0.2}-4[/tex]
[tex]=1+\sqrt{1}[/tex]
= 1 + 1
= 2
Thus, the value of y is equal to 2.
