tayfkay33 tayfkay33
  • 06-02-2020
  • Mathematics
contestada

In JKL, solve for x.
A.66.73
B.15.44
C.38.16
D.74.89

In JKL solve for x A6673 B1544 C3816 D7489 class=

Respuesta :

maximumride14
maximumride14 maximumride14
  • 06-02-2020
The answer is b 15.44
Answer Link
jimrgrant1 jimrgrant1
  • 06-02-2020

Answer:

D

Step-by-step explanation:

Using the sine ratio in the right triangle

sin27° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{KL}{JL}[/tex] = [tex]\frac{34}{x}[/tex]

Multiply both sides by x

x × sin27° = 34 ( divide both sides by sin27° )

x = [tex]\frac{34}{sin27}[/tex] ≈ 74.89 ( to 2 dec. places ) → D

Answer Link

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