lejeunee1039 lejeunee1039
  • 06-02-2020
  • Physics
contestada

A 5.00 liter balloon of gas at 25°C is cooled to 0°C. What is the new volume (liters) of the balloon?

Respuesta :

Netta00 Netta00
  • 06-02-2020

Answer:

4.58 L.

Explanation:

Given that

V₁ = 5 L

T₁ = 25°C  = 273 + 25 = 298 K

T₂ = 0°C = 273 K

The final volume = V₂

We know that ,the ideal gas equation

If the pressure of the gas is constant ,then we can say that

[tex]\dfrac{V_2}{V_1}=\dfrac{T_2}{T_1}[/tex]

Now by putting the values in the above equation we get

[tex]V_2=V_1\times \dfrac{T_2}{T_1}\\V_2=5\times \dfrac{273}{298}\\V_2=4.58\ L\\[/tex]

The final volume of the balloon will be 4.58 L.

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