Answer:
K = 500 x 10⁶ MPa
Explanation:
Given that
P = 10 MPa
V= 0.25 m ³
Reduction in the volume ,ΔV=- 0.005 cm³
We know that 1 m = 1000 cm
ΔV=- 0.005 cm³ = - 0.005 x 10⁻⁶ m³
We know that bulk modulus given as
[tex]K=-\dfrac{P}{\dfrac{\Delta V}{V}}[/tex]
Now by putting the values
[tex]K=-\dfrac{10}{\dfrac{-0.005\times 10^{-6}}{0.25}}[/tex]
We get
K = 500 x 10⁶ MPa
Therefore the bulk modulus of the elasticity will be 500 x 10⁶ MPa.
