Answer:
Solutions do not exist.
Step-by-step explanation:
[tex]2sin\frac{x}{3}+3=0\\sin\frac{x}{3}=-\frac{3}{2}[/tex]
Range of sin function is [-1,1].
It can only take values varying from -1 to +1 (including both).
Hence [tex]sin\frac{x}{3}[/tex] cannot be -3/2.
Therefore the above equation has no solution.
