Answer:
Distance from the point to the line will be [tex]\sqrt{5}m[/tex]
Step-by-step explanation:
We have given the equation of the line is y = 2x\
So the equation of line will be y-2x = 0
Point from which we have to find the distance is (-2,1)
Distance from a point to line is given by [tex]d=\frac{Ax+By+C}{\sqrt{A^2+B^2}}[/tex] , here A = -2 , B = 1 and C = 0
And point x = -2 and y = 1
So [tex]d=\frac{-2\times -2+1\times 1+0}{\sqrt{(-2)^2+1^2}}=\sqrt{5}m[/tex]
So distance from the point to the line will be [tex]\sqrt{5}m[/tex]
