Answer:
34 g of NH₃ were produced in the reaction
Explanation:
N₂ (g) + 3H₂ (g) → 2NH₃ (g)
Moles of N₂ → 28 g / 28 g/m = 1 mol
Moles of H₂ → 25g / 2 g/m = 12.5 moles
Clearly, the limiting is the nitrogen.
1 mol of N₂ produced 2 moles of ammonia
So, If I have 1 mol, I'll produce the same amount
2 moles of NH₃ = Mol . Molar mass
2 m . 17 g/m = 34 g
