Answer:
The Answer is option C.) 1
[tex](2x)^{0} = 1[/tex]
Step-by-step explanation:
Given:
[tex](2x)^{0}\\[/tex]
Solution:
Law of Indices:
[tex](x\times y)^{a} = x^{a}\times y^{a}[/tex]
Also,
[tex]a^{0} =1\\or\\(anything)^{0} = 1.......Always[/tex]
Now we have,
[tex](2x)^{0}=(2^{0}\times x^{0})\\\\(2x)^{0}=(1\times 1)\\\\(2x)^{0}=1\\\\\therefore (2x)^{0}=1[/tex]
The Answer is option C.) 1
∴ [tex](2x)^{0} = 1[/tex]
