Answer:
B
Step-by-step explanation:
Using the rules of exponents
[tex](a^mb^n)^{p}[/tex] = [tex]a^{mp}[/tex] [tex]b^{np}[/tex] and
[tex]a^{-m}[/tex] ⇔ [tex]\frac{1}{a^{m} }[/tex]
Given
[tex](9c^{-9}) ^{-3}[/tex]
= [tex]9^{-3}[/tex] [tex]c^{-9(-3)}[/tex]
= [tex]\frac{1}{9^{3} }[/tex] [tex]c^{27}[/tex]
= [tex]\frac{1}{729}[/tex] [tex]c^{27}[/tex] → B
