Answer:
20 drops of ethanol dispensed by dropper will be 1.0 mL ethanol.
Explanation:
Mass of 15 drops of ethanol = 0.60 g
Mass of 1 drop of an ethanol = [tex]\frac{0.60 g}{15}=0.04 g[/tex]
Mass of 1.0 mL of ethanol = m
Volume of ethanol = 1.0 mL
Density of an ethanol = d = 0.80 g/ml
[tex]m = d\times V =0.80 g/mL\times 1.0 mL=0.80 g[/tex]
Number of drops in 0.80 g of ethanol = x
[tex]x\times 0.04 g=0.80 g[/tex]
[tex]x=\frac{0.80 g}{0.04g}=20 [/tex]
20 drops of ethanol dispensed by dropper will be 1.0 mL ethanol.
