chanceblair6384 chanceblair6384

07-11-2019
Physics

contestada

A 6kg rock is thrown vertically upward from the top of a cliff that is 28m high. It was thrown with a speed of 11ms . Calculate the greatest height of the rock as measured from the base of the cliff.

Respuesta :

sodiqolamilekan69 sodiqolamilekan69

08-11-2019

Answer:H=34.05m

Explanation: H=u²/2g+ 28m height of the cliff

u=11ms⁻¹

g=10ms⁻²

H=11²/2*10

H=121/20

H=6.05+28

H=34.05m

Answer Link

Otras preguntas

What is 3.14 in math

hey guys, if you will please tell what does the expression "take it easy" mean?

what criteria must be met to ensure that someone is an eligible voter?

nine less than four times a number equals fifteen

List three ways governments could pay for the war. (Civil War)

Does anyone know how to do this? I can only get one answer :/Solve the equation:sin (x + 80°) = 0.6for -180° < x 180°Ans - x = –86.26° or 126.26°

why does your eyes burn

In Brazil the indigenous population was around 3.5 million before the arrival of European today the indigenous population is around

The museum charges $12.50 for youth admission and $17.50 for adults. One day the museum collected $1535 from a total of 110 youths and adults. How many admis

I need help with this Algebra question?