Respuesta :

bridgetwelborn

Answer:

Explanation:

In this problem, a 10 - 10 M solution of HCl contributes 10 - 10 M [H +]. The ionization of water contributes 10 - 7 M [H +].

znk

Answer:

4

Explanation:

HCl ⟶ H⁺ + Cl⁻

HCl dissociates completely in solution, so

1.0 × 10⁻⁴ mol·L⁻¹ HCl ⟶ 1.0 × 10⁻⁴ mol·L⁻¹ H⁺

pH = -log(H⁺) = -log(1.0 × 10⁻⁴) = -log(1.0) - log(10⁻⁴)= -0 - log(-4) = -(-4) = 4