For this case we have the following functions:
[tex]f (x) = 7\\g (x) = x-4[/tex]
We must find[tex](g_ {0} f) (x)[/tex]. By definition we have to:
[tex](g_ {0} f) (x) = g (f (x))[/tex]
So:
[tex](g_ {0} f) (x) = (7) -4 = 7-4 = 3[/tex]
Then, regardless of the value of "x", [tex](g_ {0} f) (x) = 3.[/tex]
Answer:
For any value of "x", [tex](g_ {0} f) (x) = 3[/tex]. Thus, [tex](g_ {0} f) (0)[/tex] cannot be evaluated, the result will always be 3.
